Math 484.1. April 19, 2006 .
Midterm 3.
5 problems, 10 pts each. Name______________
Solve matrix games:
1.
1
|
2
|
3
|
4
|
5
|
3
|
3
|
4
|
5
|
4
|
5
|
4*'
|
6
|
4
|
5
|
5
|
1
|
4
|
3
|
2
|
4
|
1
|
2
|
1
|
3
|
*' saddle point.
2.
1
|
2
|
3
|
4
|
5
|
3
|
1
|
4
|
5
|
4
|
3
|
1
|
2
|
3
|
1
|
5
|
1
|
4
|
3
|
2
|
4
|
1
|
2
|
1
|
3
|
By domination, we get
Row player's optimal strategy is (4r1+r4)/5 = [0.8, 0,
0, 0.2, 0]T. Column player's optimal strategy is
(c1+4c2)/5 =[0.2, 0.8, 0, 0, 0].
The value of game is 9/5 = 1.8.
3.
2
|
0
|
2
|
-2
|
2
|
-2
|
0
|
5
|
4
|
2
|
-5
|
0
|
The first column goes by domination. Then we get a symmetric game, so
its value is 0.
An optimal strategy for the column player is [0, 5, 2, 2]/9,. Its
transpose without the first entry is an optimal strategy for the
row player .
4.
3
|
3
|
0
|
1
|
4
|
1
|
0*'
|
1
|
0
|
2
|
3
|
3
|
2
|
2
|
0
|
1
|
2
|
2
|
0
|
1
|
2
|
0
|
0
|
1
|
*' saddle point.
5.
1
|
4
|
3
|
2
|
5
|
4
|
3
|
5
|
4
|
3
|
1
|
4
|
3
|
1
|
5
|
4
|
5
|
2
|
5
|
6
|
3
|
5
|
6
|
4
|
The columns 4-8 go by domination. Optimal strategies: [9, 6, 7]/22T
and [[3, 7, 1, 0, 0, 0 , 0,0]/11.
The values of game is 34/11.